Consider a point charge Q at the origin. For Q > 0, the work
done against the repulsive force on the test charge is positive. Choose a
convenient path along the radial direction from infinity to the point P.
At some intermediate point P′ on the path, the
electrostatic force on a unit positive charge is
where rˆ′ is the unit vector along OP′. Work done
against this force from r′ to r′ + ∆r′ is
The negative sign appears because for ∆r′ < 0,
∆W is positive. Total work done (W) by the external force is obtained by
integrating from r′ = ∞ to r′ = r,
This, by definition is the potential at P due to
the charge Q
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