In parallel combination of two resistors, the charge that flows
in at A from the left flows out partly through R

_{1}and partly through R_{2}. The currents I, I_{1}, I_{2}shown in the figure are the rates of flow of
Charge at the points indicated. Hence,

The potential difference between A and B is given
by the Ohm’s law applied to

**. Also, Ohm’s law applied to***R*_{1,}V = I_{1}R_{1}**gives***R*_{2}*V = I*_{2 }R_{2 }

_{}
If the combination was replaced by an equivalent
resistance

**, by Ohm’s law***R*_{eq}
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